Getting the most out of your Tests

Everyone knows that you should revise before a test – you have to prepare and write you bound reference, review all the things that might be on the test, and practice any tricky skills… That’s straight forward – any student knows that!

But who knows that you should revise after the test?

That’s silly, isn’t it? The test is over, you don’t need that material any more – the exam is a long time away! It’s all over and done with, right?

Well, to put it simply, NO!

This is the best time to revise! Your skills and understanding are at their peak – you have learned even more than before the test – you now know something you didn’t before the test – you know what you didn’t know but thought you did!

This is the best time to revise, because you are ready to finish your studies of this topic by ensuring that you have all the information you need – including fixing up those parts you thought you understood, but weren’t able to demonstrate on the test.

We worked in class recently to create a partial list of the concepts we covered throughout trigonometry – you weren’t allowed to copy the list I made, but had to organise the ideas in a way that made sense to you. Most of you know about mind (or concept) maps, but here is a great video that may help you think about them in a different way:

Here are some different graphic organisers that may help you (some are *terrible!*, some are good, some are great. You will have to find one that is most effective for you. Links: 1, 2, 3. You must produce a *quality* organisation of the concepts in Trigonometry. This task is not optional!

After our test, you were asked to write down four “parts” immediately:

Part 1: A question you did not know how to answer

Part 2: A question you attempted, but think you may have gotten wrong

Part 3: A challenging (or interesting/difficult) question you are confident you got right

Part 4: A questions that should have been (or should not have been!) on the test.

I also provided you with two documets – The Yay-Doh-Huh question sheet, and the Family Guy Post-assessment planning.

Each of you must write a comment on this post about one (or more!) of those parts, and fill in at least one of the sheets. You will have access to your test early next week, after I mark them.

Finally, each of you were in a team to talk about how you solved one of the ICAS questions. I expect a comment from each team (with replies from other team members) to discuss *how* you knew what to do to solve the problem. I want *more* than just a statement of the answer! You must show others how you thought about the problem, and what steps you went through to solve it.

So, in summary, each of you must write two comments: One reflecting on one of the “Parts” of your reaction to the test, and one discussing what problem solving techniques you used on the ICAS question (or a reply adding to the discussion if you team partner got in first!)

See you in class!

Explore posts in the same categories: Assessment, Mathematics

16 Comments on “Getting the most out of your Tests”

  1. Prathu Khairnar Says:

    First thing

    Part1: I thought that the quesiton in section G, Question 1 was a little hard, it didnt make sense to me, it was something about a box (with dimensions, 3x,4x and x)… and then there was a pole? i dont know where the pole was supposed to go?

    Part 2: Section E, question 4, a triagle with “a=4.5, b=12.8, and A=58” how many triangles can be constructed withthis information given?

    Part 3: Section A, question 6, convert “237” into binary… i am confident that i got this one right.

    Part 4: section A, question 6, i dont think this question was supposed to be on the test? was it?… i mean we were being tested one our “trig skills”, i feel unfair towards the people who didnt know what binary was.

    • Prathu Khairnar Says:

      ICAS QUESTIONS: PAPER H, QUESTION 29 – Prathu and Damien

      29) During his last holidays Tony went to a resot.

      During the day tony either relaxed all day or he did one activity for half a day and relaxed the other half of the day. the activites were bushwalking in the morning and swimming in the afternoon.

      Altogether there were 19 mornings when he relaxed, 10 afternoons when he relaxed, and a total of 15 days when he either went bushwalking or swimming.

      How many days did tony stay at the resort?

      A) 22
      B) 25
      C) 29
      D) 44

      we started doing this problem by first ploting down what tony might have done?
      heres a rough table i have drawn… or click on the link “” to look at the full working out.

      – morning- -afternoon-
      relaxed relaxed
      relaxed swimming
      bushwalking relaxed

      we will classify the days when he relaxed the whole day as “RR”, and “RS”, for swimming half the day, and “BS” for the bushwalking activity

      now we know that the total mornings he relaxed were 19.

      so we have our first equation: “RR” + “RS”= 19

      second equation shall be: “RR” + “BR”= 10, for all the afternoons relaxed,

      and finally for the day when he did the activity : “RS” + “BR”= 15

      now we have our three equations, now it would be a good idea to replace “RR”s with “A”, “RS” with “B”, and “BR” with “C”… so that it is easier to enter it in the calculator, for “3 simlutenuse equations”

      “RR” + “RS”= 19
      “RR” + “BR”= 10
      “RS” + “BR”= 15

      so the equations now look like this:

      ——- after entering them in the calculator—–

      we find that A= 7, B=12, and C=3
      which means that, there were 7 days when he relaxed all day… 12 days, when he went for bushwalking, and 3 days when he went for swimming

      now all we have to do is add them together, 7+12+3= 22

      ahhh we found our answer!!!!!….. its 22

      tony stayed at the resort for 22 days, the asnwer is A).

  2. Tia Says:

    Explanation of ICAS question:
    The question stated that there was a ferris wheel of diameter 24 m, 6 m from the ground. The wheel completes one revolution every 48 seconds. There is a car attached to the ferris wheel at the bottom. How high above the ground in metres will the car be in 18 secs later?

    a) 18 + 6 root 2
    b) 18 + 12 root 2
    c) 24
    d) 30
    The car would be one half of the way through the top left quarter after 18 seconds . We already know that from the middle point of the circle to the ground is 18 m, so all we need to do is draw a triangle within the circle, and work out the height of that triangle (adding it to the figure we already know). The angle of the triangle at the centre of the circle is 45 degrees (we know because the car sits at the mid-point of that quarter of the circle, 90 degrees). The hypotenuse/radius is 12 m (we know because the diameter is given as 24 metres). The other two sides of the triangle are unknown, but we know they are equal to each other.
    From here we can use Pythagoras’s theorem: a^2+b^2=c^2
    x^ =√72
    Plus 18 m gives us the answer as a) 18 + 6 root 2

    • Tia Says:

      Part 1 – I did not know how to solve the base 8 to binary 237 question.
      I also was unsure of what was expected of the table with questions such as solve sine(pi take theta) if sine theta eqals 0.4.

  3. Prathu Khairnar Says:

    ANOTHER ICAS QUESTION, PAPER J (the year 12 one), QUESTION 36.

    — free response question—–
    36) The line “x+y=3” intersects the parabola “y= (x^2) + 1” at points A and B. C is the vertex of the parabola what is the area of the triangle ABC, in square units?


    we started with, drawing one rough and quick diagarm, by doing this we get a quick orientation on the triangle, what its size roughly is? and all that kind of stuff.


    now the first thing we have to in this problem is that to state, where the points are.. we can find the vertex of the parabola ver easily… “Y=(X^2)+ 1”.. see that “+1”? well thats the y-intercept.. so our first point, C is (0,1)

    and now by doing the simultenuse equations of the linear(straight)line and quadratic equation… we would be able to find out the other two points, A and B.


    and now with these new points we can plot them …


    now, to find the area.. we could draw a square around the triangle, so it is easier to find the area…by doing so we could divide the shape into 4 pieces.


    we can find the sides of the rectangle we drawn on outside the triangle by subtracting the coordinates (KNOW DISTANCE METHOD) from each other.


    so now we have found the dimensions of the rectangle…now we have to find the areas of the other triangles…


    by using the same method, of subtracting the coordinates (KNOWN DISTANCE METHOD)… we can find the distances of all the other sides.. because these triangles allign perfectly along the aixs’ unlike triagnle ABC


    and now all we have to is find the area of the big rectangle and subtract the the little triangles form it… so we get the area of the triangle ABC

    (4 x 3) – [ (4 x 2/2) + (1 x 1/2) + (3 x 3/2) ]

    area of triangle ABC = 3 units ^2

    ———-Phew!!! the end!! ==”

    so much typing…

  4. Ellayne Says:

    Parts of Test Reflection:

    Part 1 – Review on Algebra question: f(x) = 15 + 4x – 4x^2, find the critical points. I don’t know what critical points are and I’m still a bit confused with solving equations like this.

    Part 2 – Section E. Question 2. I tried to think about the table: given that sinθ=0.4, then solve sin(-θ), but I’m still unsure of my answer.

  5. Renata Says:

    Part 1: A question you did not know how to answer
    base 8 to binary 237 question.
    E. Question 2
    f(x) = 15 + 4x – 4x^2
    a=4.5, b=12.8, and A=58

    icas Question
    Milica and Renata
    The radius of the base of a cylinder is 7.5cm and its height is 30cm.
    what is the area of a paper used to cover around the cylinder to the nearest cm.
    Well we knew the formula of the area of a cylinder is (area of 2 circles + area of curved surface) 2πr^2 +2Vrh. so we just used 2Vrh to find the area.

  6. Hao Says:

    Part 1 – Review on Algebra Question.
    f(x) = 15 + 4x – 4x^2, find the crit. points.
    I think I can do this, I have seen these types of questions before. But my memory of how do to them is very vague.

    Part 2 – ***Still unsure about***

    ICAS Question
    Hao & William
    *Tina, Olivia and Natalie are standing an equal distance from each other. Tina is pointing at Olivia. She turns so that she is pointing at Natalie.
    What is the smallest number of degrees that Tina could have turned?*

    We know that they are standing in a triangle, because the 3 of them represent the vertices.
    We also know that they are standing an equal distance from each other.
    This suggests that they make an Equilateral Triangle.
    And the smallest angle you can make from an Equilateral Triangle is “60 degrees”.

  7. Jana Says:

    for the ICAS thing:
    what is 7.34% equal to?
    answer = 0.0734

    to convert from a percentage to decimal, we divide by 100.
    so 7.34/100 = 0.0734

    to check this we can do the reverse.
    converting decimal to percentage, we multiply by 100.
    so 0.0734 x 100 = 7.34

  8. Nini Phan Says:

    PART 1: A question you did not know
    i didn’t know how to solve the base 8 to binary 237

    PART 2: A question you attempted, but think you may have gotten wrong
    I attempted the drawing of bearings, I’m not sure if i got it all corrected

    PART 3: A challenging (or interesting/difficult) question you are confident you got right
    Question 2 and 3- the cliff question

    PART 4: A questions that should have been (or should not have been!) on the test.
    I think the question that should have not been on the test was the 3D trigonometry

  9. Ellayne Garcia Says:

    In an irregular quadrilateral ABCD, given 3 of the angles as a right angle, 100 – 2x and 80 + x, find an expression for the size of angle A in degrees.

    a) (x + 90)
    b) (x – 90)
    c) (-3x + 90)
    d) (-3x – 90)
    So with this problem, we’re dealing with the internal angles of a polygon, particularly an irregular quadrilateral. The internal angles of a quadrilateral add up to 360deg. Therefore, we could express these angles as:

    360 = <A + <B + <C + <D
    360 = <A + (80 + x) + (90) + (100 – 2x)
    360 = <A + 270 – x
    ∴90 + x = <A

    We could check our answer by adding up all angles.
    360 = (80 + x) + (90) + (100 – 2x) + (90 + x)
    360 = (80 + 90 + 100 + 90) + (x +x – 2x)
    360 = 360

    Therefore, our answer is a) (x+90).

  10. Bernice Says:

    Part A- question didn’t know how to solve
    (was already answered in class, the base 8 to binary 237 question)

    Part B- question tried

    Section D Q9
    Write an equation involving the smaller and larger triangle

    Part C- question that you are confident in

    Section E Q5 and 6
    Find the angle of ABC and side of AB

    Part D- question that shouldn’t be on the test

    Section G Q2

    Plot the following equation
    f (x) = 15 + 4x = 4x^2

  11. Manar Says:

    Hey Sir, My post assesment for the trigonmetry test is as follows:

    PART 1: A question I did not know how to solve was converting base 8 to binary 237.

    PART 2- A question I attempted was the one where it had sin, cos , tan and π and we had to use the table to solve what pi- theta would equal. I think I may of done this wrong.

    PART 3- A question I am confident I got right was question 5 and 6 in Section E where we had to find angle <ABC and the side AB.

    PART 4- A question that I think should not have been on the test was converting base 8 to binary 237.

  12. Andrea Says:

    I found that I had no idea how to even begin question 2, section E.
    If sin∅=0.4, cos∅=0.9 and tan∅=0.5, write the value of the following:
    a. sin⁡(π-∅)
    b. tan(2π-∅)
    c. tans(-∅)

    I attempted to do question 4, section E
    Billy-bob drives 15kms N35W and then 22kms S22E. How far are you from the starting point.

    Whilst question 3, section E appears to be challenging, I found it enjoyable and more simple when I broke it up.

    I think that more trigonometry ratios would have been good, since we spent a while doing them. I was a bit disappointed that I couldnt use those skills.

  13. Damien Meyepa Says:

    Test Reflection
    PART 1: A question I did not know how to solve was converting base 8 to binary 237.

    PART 2- A question I attempted was to convert radians to degrees ect.

    PART 3- A question I am confident I got right was drawing the bearings.

    PART 4- A question that I think should not have been on the test was converting base 8 to binary 237.

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